(x+1)(x+2)(x+3)(x+4)=120 /Quadratic Equation - Problem-1 - Mathematics@academia online - Mathematics

Published 2019-12-29

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(x+1)(x+2)(x+3)(x+4)=120 /Quadratic Equation - Problem-1 - Mathematics@academia online - Mathematics

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RÉSOUDRE (x+1)(x+2)(x+3)(x+4) = 120

[(x+2)(x+3)(x+4)(x+5)]/[(x-2)(x-3)(x-4)(x-5)] = 1 || Sabes cómo resolver esta bonita ecuación

x(x+1) (x+3) (x+4) = 180 || Can you solve this?

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factorize (x+1)(x+2)(x+3)(x+4)-120. ❤️❤️❤️❤️

One root of the equation `(x+1)(x+3)(x+ 2) (x + 4) = 120` is:

Solve for : `x :(x-1)/(x-2)+(x-3)/(x-4)=3 1/3,x!=2,4`

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