Proving -1/2 ≤ ab+ac+bc ≤ 1 for a^2+b^2+c^2=1 Published 2021-12-30 Download video MP4 360p Download video MP4 720p Recommendations 07:21 Sum k=1 to 2021 (k^2+3k+1)k! 09:49 Let's Solve A Nice Tangential Differential Equation 08:22 A Cubic Functional Equation Solved in Two/Three Ways 08:17 Proving An Inequality With Factorials 08:11 A Very Quartic Equation | Can You Solve? 08:35 A Polynomial Equation | Math Competitions 10:02 f(x+sqrt(x))=x-sqrt(x). Finding f(12) in Two Ways 3:59:44 Algebra 2 Introduction, Basic Review, Factoring, Slope, Absolute Value, Linear, Quadratic Equations 1:07:12 NES Emulator Part #2: The CPU (6502 Implementation) 08:50 Solving Two Functional Equations 49:57 Jak działa czarna dziura? / prof. dr hab. Andrzej Dragan 16:31 Парадокс производной | Суть Матанализа, глава 2 10:21 Comparing 999! and 500^999 in Two Ways 07:30 Proving the Inequality a(a+b)+b(b+1) ≥ -1/3 20:59 A very nice olympiad question | How to solve (4 + sqrt{5})^x + (4 - sqrt{5})^× | Algebra | 15:55 Visualize Spectral Decomposition | SEE Matrix, Chapter 2 06:28 A tricky fraction question from India! Similar videos 04:08 Prove that: `|(a^2+1, ab, ac),(ab, b^2+1, bc),(ac, bc, c^2+1)|=1+a^2+b^2+c^2` 06:41 XII Determinants Prove that a^2 +1 ab ac ab b^2 +1 bc ca cb c^2 +1 = 1 + a^2 + b^2 + 02:31 Proof of Area of a triangle = 1/2absinC | ExamSolutions 03:33 Show that ` |[1,a,a^2],[1,b,b^2],[1,c,c^2]|=(a-b)(b-c)(c-a) ` 04:11 An Algebra Problem | a+b+c = 2 , ab+bc+ca = 1 , (a+b)^2 + (b+c)^2 + (c+a)^2 = ? 01:20 Area of Triangle 1/2absinC c | Trigonometry | Maths | FuseSchool 03:53 A Nice Algebra Question | ab + bc + ca = 0 , 1/a^2-bc + 1/b^2-ca + 1/c^2-ab = ? 03:38 `|[1, b+c, b^(2)+c^(2)], [1, c+a, c^(2)+a^(2)], [1, a+b, a^(2)+b^(2)]| = (a-b)(b-c)(c-a)` 05:30 Using properties of determinant, prove that `abs{:(1,a,a^2),(1,b,b^2), | Class 12 Maths | Doubtnut 08:45 Area of ∆ABC=1/2 bc sinA=1/2 ac sinB=1/2 ab sinC. Proof of triangle by using trigonometry concept 08:08 `([1,1,1],[a,b,c],[a^2,b^2,c^2])=(a-b)(b-c)(c-a)` 05:31 Prove: `|(1,a, b c),(1,b ,c a),(1,c ,a b)|=|(1,a ,a^2),( 1,b,b^2),( 1,c,c^2)|` 02:46 If ab + bc + ca = 0 then the value of 1/(a^2-bc)+1/(b^2-ca)+1/(c^2-ab) 01:49 If 𝒂𝒃+𝒃𝒄+𝒄𝒂=𝟒 and 𝒂𝒃𝒄=𝟐, then find the value of 𝟏/𝒂+𝟏/𝒃+𝟏/𝒄 00:15 Memorization Trick for Graphing Functions Part 1 | Algebra Math Hack #shorts #math #school 02:47 Q344 | If ab+bc+ca=0, then what is the value of 1/(a^2-bc)+1/(b^2-ca)+1/(c^2-ab)? | Algebra 10:50 Class 12 Maths By using properties of determinants R B Classes 03:05 If `a^2+b^2+c^2=1` then `ab+bc+ca` lies in the interval 02:57 Area Of A Triangle 1/2absinC | Trigonometry | Maths | FuseSchool More results