`int_(0)^(pi//2) (x sin x cos x)/(sin^(4) x+cos^(4) x) dx` का मान ज्ञात कीजिए।

Published 2020-03-29

Recommendations

Similar videos

02:27

If `int_(0)^(pi//2)sin^(4)x cos^(2)x dx=(pi)/(32)`, then `int_(0)^(pi//2)sin^(2)x cos^(4)x dx=`
04:06

Q7 | Prove that Integral 0 to pi/2 sin ^4 x / sin ^4 x + cos ^4 x dx =pi/4 | sin 4x / sin 4x + cos4x
04:06

`int_(0)^(pi) xsin x cos^(4)x dx=`
09:20

Q8 | Integration of sin x + cos x upon 9 + 16 sin2x | Integration of (Sinx + cosx )/(9 + 16sin2x)
15:19

Integral 0 to pi/4 sin x cos x by cos^4x + sin^4x detailed solution in three ways by Dig Your Mind
03:24

Evaluate `int _(0)^(pi//2) sin^(4) x. cos^(6) x dx`.
12:19

Prove that Integral 0 to pi/2 sin ^4x / sin ^4 x + cos ^4 x dx = pi/4 || sin 4x / sin 4x + cos4x dx
05:30

`int_(0)^(pi//4)(sin x + cos x)/(9+16 sin 2 x )`
34:12

Limit 0 to π/2 integrate Sin^2 (x)/(1+Sinx•Cosx)dx | Integral Sin^2 xdx/(1+Sinx Cosx)from 0 to pi/2
03:42

`int_(0)^((pi)/(4))(sinx +cos x)/(9+16 sin 2x)dx`
04:30

Prove that `int_0^pi x sin^6xcos^4xdx=pi/2 int_0^pi sin^6xcos^4xdx`
$Evaluate: ( int_{0}^{pi / 4} frac{sin x+cos x}{16+9 sin 2 x}...$ 09:27

Evaluate: ( int_{0}^{pi / 4} frac{sin x+cos x}{16+9 sin 2 x}...
10:48

Integral 0 to pi/4 (Sin x + Cos x) dx / 9 + 16 Sin 2x @EAG
More results