Expand f(x)=x sin〖x 〗 as fourier series in (-π,π). Deduce that 1/1.3-1/3.5+1/5.7-1/7.9……..=(π-2)/4 Published 2021-06-13 Download video MP4 360p Recommendations 21:28 @btechmathshub7050Fourier series f(x)=xsinx 40:39 Find Fourier series for f(x)= xsinx for x in interval [-π,π]. Hence find 1/1.3-1/3.5+1/5.7= (π-2)/4 22:12 Find fourier series expansion of f(x) | fourier series dirichlet condition @SwatiThengMathematics 16:36 Fourier Series 25:12 Find Fourier series for neither even nor odd function (-π,π) Examples -Fourier Series 16:21 Fourier Half range cosine series of xSinx || 18mat31 || Dr Prashant Patil 16:50 Expand f(x)=x cos〖x 〗 as Fourier series in the interval (-π,π) 17:53 FOURIER SERIES f(x) = |cos x| in interval x (- pi to +pi) 13:10 Fourier series of f(x) = (pi-x)/2 x= 0 to 2pi Deduce Π/4 = 1 - 1/3 + 1/5 - 1/7 + ... 19:43 Expand f(x)=x as a Fourier series in(0,2π).| Fourier series | Lec320 14:52 @btechmathshub7050 Fourier series of f(x)=x² 25:34 Fourier series of a function || x-x^2 || which is nighter even nor odd || 18mat31 15:46 @btechmathshub7050Fourier series f(x)=|sinx| 30:46 Fourier Series of f(x)= xsinx in interval 0 to 2π in hindi 12:57 Complex Fourier Series (fourier series engineering mathematics) 14:36 Fourier series example f(x)=x^2 in 0 to 2pi 20:29 When Nakamura gets Pragmatic | Pragg vs Naka | FIDE Candidates 2024 23:12 Fourier Series of x sinx || as even function || in the interval -π to π || 18mat31 12:47 Fourier series of f(x)=x-x^2 -pi to pi Deduce Π^2/2 = 1+1/2^2 + 1/3^2+... Similar videos 48:09 Fourier Series #3 (M.M.Imp. Numerical Problem) #FourierSeries #EngineeringMathematics #BScMaths 29:31 Fourier Series #5 (Imp. Numerical Problem) #FourierSeries #EngineeringMathematics3 #BScMaths 13:51 Fourier Series Examples and Solutions | Problem #1 | Numericals | Periodic Function | Period 2pi 14:05 Lecture 4. Fourier Series Numerical. 13:48 Fourier Series of (x-x^2): Full Calculation 24:43 8. Fourier Series | Discontinuity | Problem#2 | Complete Concept | Most Important Problem 24:30 Fourier Series: Sum of 1/n^4 = pi^4/90, Sum of 1/(2n-1)^2 = pi^2/8 12:25 Fourier series of f(x)=-k x=-pi to 0 k x=0 to pi Deduce Π/4=1-1/3+1/5-... 14:51 FOURIER SERIES: f(x) = √1-cos x in (x=0 to 2Π) Find the value of 1/1*3 + 1/3*5 + 1/5*7 +... 27:56 Fourier series of f(x)= xsinx, 16:40 FOURIER SERIES f(x) = pix x=0 to 1 pi(2-x) x=1 to 2 Deduce Π^2/8 = 1 + 1/3^2 + 1/5^2 +... 09:39 Fourier series f(x)= |x| in the interval -pi to pi 37:27 Fourier Series #7 (V.Imp) | Discontinuous Function | Function having Finite Points of Discontinuity 14:18 7. Fourier Series | Discontinuity | Problem#1 | Complete Concept | Most Important Problem More results